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Given a random list of numbers, your task is to find the two indices that added together equal the

targetnumber.For example:

numbers = [3, 10, 14, 8, 15, 5, 16, 13, 9, 2] target = 30 result = (2, 6)To make it a bit harder there are some conditions you should meet:

- the number at index 1 < number at index2
- if there are multiple indices leading to the right
targetnumber, you must return the one where the number at index 1 is the smallest, so if we need to get to 5224 (used in one of the tests) and we have the following contenders the former wins, because it has the smallestvalueat thefirstindex:index 31: 476 index 42: 4748 total: 5224 index 21: 1675 index 29: 3549 total: 5224You can assume that each solution only has one correct answer. If no solution can be found, just return

`None`

. Good luck!You are free to implement it as you want, but for the fastest solution you might want to follow these steps (again, not required): assuming we have two indices pointing to two of the values in the numbers list,

`i`

and`j`

. The sum of`i`

and`j`

could only fall into one of these three possibilities:

`i + j > target`

- increasing`i`

ins't going to help us, as it makes the sum even bigger. Therefore we should decrease`j`

`i + j < target`

- decreasing`j`

isn't going to help us, as it makes the sum even smaller. Therefore we should increase`i`

`i + j == target`

- We have found the answerThis challenge was adapted from Leetcode Clean Code Handbook

Round of applause for @clamytoe for delivering this Bite.